[求助]求矩量法分析的一些程序,有角反射天线的最好

那位大大有啊,跪求 20)8e!jP  
[email]iqu8@qq.com[ .. K?=g IC:  
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同求cutejltong@163.com

#这是一个大锅的反射计算程序 JiCy77H  
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# wire array in a semi circle VHTr;(]hk  
from scipy import * [7gwJiK  
from scipy.special import * !7aJfs2  
is}Y+^j.  
# define the constant T>pz?e^5&  
IDM=90 # dimension index for x and y coordinates ^ot9Q  
X=zeros(IDM,float) 2?\L#=<F  
Y=X.copy() "SN+ ^`  
I=X.copy() # current on each wire &p:GB_  
RHO=zeros((IDM,IDM)) nAW`G'V#  
A=RHO.copy() # [A][I]=[B] 6O'6,%#  
B=zeros((IDM,1)) # field at observation point &Ch~$Wb^  
LAMDA=1.0 # normalized wavelength 'Mm=<Bh  
#N=30 # number of cylinder wires R%^AW2   
THETA0=pi/2.0 # incidence angle in respect to z diretion Z1M{5E  
PHI0=0.0 # incidence angle on x-y plane in respect to +x direction f)!7/+9>  
E0=1.0 # virtual incident wave field strength 1V/m L=5
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R=1.125*LAMDA # radius of array f2RIOL,  
K=2*pi/LAMDA # wave constant J1{ucFa  
AA=0.05/K # radius of wire JM Ikr9/$  
S=1.0/K S*?x|&a  
H=K*cos(THETA0) # wave propagation constant on +z direction PU^@BZ_m  
G=sqrt(K**2-H**2) # transverse wave constant A0 1D-)  
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# define the wire location AND RHO ^ ]CQd   
PHI=zeros(IDM,float) q.NvwJ  
for m in range(IDM): ?u_O(eg  
    PHI[m]=-0.5*pi+pi*float(m)/float(IDM) 5mB'\xGO2  
    X[m]=R*cos(PHI[m]) rty&\u@}  
    Y[m]=R*sin(PHI[m]) /V)4B4  
     cp<jwcc!  
# construct matrix [A] [B] #g
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for m in range(IDM): hZNAI  
    for n in range(IDM):  L\("  
        if (m-n): g\foBK:GE  
            RHO[m,n]=sqrt((X[m]-X[n])**2+(Y[m]-Y[n])**2) :_"%o=  
        else: |!H@{o  
            RHO[m,n]=AA d3K-|  
        ARGU=G*RHO[m,n] Hnc<)_DF  
        A[m,n]=hankel2(0,ARGU) @mId{w z  
    ALPHA=X[m]*sin(THETA0)*cos(-PHI[m])+Y[m]*sin(THETA0)*sin(-PHI[m]) # incidence wave c9)5G+   
    B[m,0]=E0*exp(-1j*K*ALPHA) ,Frdi>7 ~  
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# solve [I]=[A]-1 [B] YR}By;Bq  
A=mat(A) # MUST FOR MATRIX INVERSION AND MULTIPLY *IBCThj  
B=mat(B) 7H5t!yk|9  
A=linalg.inv(A) <.B^\X$  
I=A*B Gmp`3  
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# calculate far field 7T}r]C.  
N=180 # number of angular PHI_FAR /f) #CR0$  
PHI_FAR=linspace(-pi,pi,N) UV8K$n<  
R_FAR=100.0*R # radius for far field caculation ZMI vzQYI  
SUM=zeros(N,complex) # scatter field at N different PHI_FAR 61{IXx_  
XOB=zeros(N, float) # rectangular coordinates of obseravation point \]+57^8r  
YOB=XOB.copy() ~7Jj\@68  
for n in range(N): qb1[-H  
    XOB[n]=R_FAR*cos(PHI_FAR[n]) u#`FkuE\}  
    YOB[n]=R_FAR*sin(PHI_FAR[n]) 2rJe
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    for k in range(IDM): IYk^eG:;
 
        Ik=I[k,0] # it is so important that result of matrix ZP^7`q)6  
                  #must be reduced to element >*cg K}!@  
        DX=XOB[n]-X[k] Ig M_l=  
        DY=YOB[n]-Y[k] '`fz|.|cbB  
        D_PHI=DX/sqrt(DX**2+DY**2) # relative angular between nth observation point and kth source JypXQC}~  
        ALPHA_S=DX*cos(D_PHI)+DY*sin(D_PHI) ,=Fn6'  
        #ALPHA_S=X[k]*cos(PHI_FAR[n])+Y[k]*sin(PHI_FAR[n]) N"q C-h  
        SUM[n]+=Ik*exp(1j*G*ALPHA_S) #Bgq]6G2  
         6`l7saHXE  
MAG_SUM=abs(SUM) +F3`?6UXz  
for n in range(N): s;4r)9Uvx  
    print PHI_FAR[n]/pi*180.0,MAG_SUM[n] ,3E9H&@j  
}MV=I$S2U  
import pylab BbdJR]N/!h  
pylab.plot(PHI_FAR/2/pi*360.0, MAG_SUM) [.`%]Z(  
pylab.show() Jh)K0>R  
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