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时域有限差分法 FDTD
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Sullivan Dennis书上1d fdtd请教
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Sullivan Dennis书上1d fdtd请教
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bo8308
UID :138
注册:
2006-11-03
登录:
2025-04-02
发帖:
51
等级:
仿真二级
0楼
发表于: 2022-02-18 14:46:51
electromagnetic simulation using fdtd method (Sullivan Dennis) 书上的1.2题matlab代码如下,不知道仿真对没?请大佬指点
/~fu,2=7
5xNOIOpDB
TM_bu
clear;
2.v`J=R
KE=200;
f.oY:3h:
ex=1:KE+1;
)-}<}< oO
ex(1:KE+1)=0;
$-!7<a-
hy=1:KE+1;
iXXaB+w
hy(1:KE+1)=0;
oblw!)
a=1:KE+1;
e},:QL0X
a(1:KE+1)=0;
U-f8D
kc = (KE / 2)+1;
Qx!Bf_,J
t0 = 40.0;
1Ak0A6E
spread = 12;
wq1s#ag<
T = 0;
_z.CV<
Time1=40;
6Iz!_
NSTEPS=Time1;
Fy$C._C$
M=moviein(Time1);
j>v8i bS(
for b = 1:Time1
Tkp"mT v?<
!/|B4Yv
for n=1:NSTEPS
7X>@r"9<
wnLpf
T=T+1;
|Dq?<Ha
for k=2:KE+1
(R RRG;*n#
dpt P(H
% ex(k) = ex(k) +0.5*(hy(k - 1) - hy(k));
0%IZ -])
%ex(k) = ex(k) +1*(hy(k - 1) - hy(k));
\RFA?PuY
% ex(k) = ex(k) +0.25*(hy(k - 1) - hy(k));
/;21?o
% ex(k) = ex(k) +1.1*(hy(k - 1) - hy(k));
)fS6H<*
ex(k) = ex(k) +0.5*(hy(k - 1) - hy(k));
QAZs1;lU
ex(1)=0;
<+b~E,
ex(201)=0;
By}ZHK94I
end
1L\r:mx3
$`0,N_C<}
if T<=100
%.\+j,G7
pulse = exp(-0.5*(power((t0 - T) / spread, 2)));
L6!Hv{ijn
ex(kc) = pulse;
{c drMP@""
else
Ip8:~Fl]
pulse = exp(-0.5*(power((t0 - T) / spread, 2)));
@j%@Z
ex(kc) = ex(kc)+pulse;
$~ d6KFT
end
+x4*T
zqI|VH
pXh`o20I
for k = 1:KE
AAB_Ytf
JEZ0O&_R
%hy(k) = hy(k) + 0.5*(ex(k) - ex(k + 1));
J^~J&
%hy(k) = hy(k) + 1*(ex(k) - ex(k + 1));
uz=9L<$
% hy(k) = hy(k) + 0.25*(ex(k) - ex(k + 1));
[E2".F3
% hy(k) = hy(k) + 1.1*(ex(k) - ex(k + 1));
w&]$!g4
& ..
P(C5@x(Z
Jk{v(W#
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bo8308
UID :138
注册:
2006-11-03
登录:
2025-04-02
发帖:
51
等级:
仿真二级
1楼
发表于: 2022-02-18 14:47:26
感觉仿真出来有数值色散,不知道哪里问题
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