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How can we calculate the radiated power in CST MWS?
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How can we calculate the radiated power in CST MWS?
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rfdesgin
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2012-01-27
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发表于: 2012-01-16 14:51:37
关键词:
CST
power
dear friends
j8`BdKg
hi
@OHm#`~
I embedded an antenna in a lossy medium and I know the S11 and deliver power 1w but i don't know, how should I calculate the radiated power?
:a)u&g@G
the return loss Figure is resonated at 402MHz to -20dB .
:/Qq@]O>
Is this solution sorrect?
?pZOeqqu$
S11=10log(P(ref)/P(inc)))=>
&! ?eL
-20=10log(P(reflected)/1w)=>P(reflected)=0.01w
?F;8Pa/
P(inc)=P(radiated)+P(ref)=>P(radiated)=0.99
*WT`o>
AzxXB
but I have a lossy medium in which the antenna is located.that is
fd2T=fz-
P(radiated)=P(pure_radiation)+P(Loss)
V$?SR44>nH
I know the SAR value 135(mw/g), but I don't know how should I calculate the P(Loss ..
= 9]~yt
w+{LAS
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lavender
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发表于: 2012-01-17 01:55:27
p(accept)=p(incidence)*s21=0.99w
$6iX
p(pure_radiation)=p(accept)*Q
aH/ k Ua
那有木有Q值啊?
k5.Lna
你知道sar没什么用吧,天线一定不是全向的吧,就算是,也反映不到该点的辐射能量密度,算不了辐射功率的吧。
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ytfbuaa
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2012-01-25
lavender
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rfdesgin
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发表于: 2012-01-17 18:32:22
sorry i don't understand exactly ,would you please explain more?
1D3dYVE
if the radiation pattern be something like this
Ew)n~!s
how we can calculate the radiated power?
&/z+A{Hi
图片:Rad.JPG
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hefang
本账号已冷冻,请勿发站内信或回帖,概不回复!
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3楼
发表于: 2012-01-20 18:23:31
回 楼主(rfdesgin) 的帖子
试着翻译一下楼主的意思,楼主是说把一个天线放置在一块有耗介质内部,现在想得到天线通过有耗介质辐射至自由空间的总功率,是吗?
66Cj=n5
Pvb+
如果是实际测量,楼主要如何得到这个参数?
C6;](rN)N
\8@[bpI@g
PS:如果可能的话,用自己的机器敲汉字吧。
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ytfbuaa
rf币
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积极参与论坛交流,欢迎继续参与本贴交流!
2012-01-25
版主周末都不回答问题?
版主要回答问题,你做到了吗?
hefang你是CST公司的吧,说点儿有用的!
你是做天线的吗?不懂不要说外行的话!
你要是不懂就shut up!
相信我,没有你论坛会更好。
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rfdesgin
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4楼
发表于: 2012-01-25 16:04:19
I found out how should I calculate the radiated power it is calculated from the radiation efficiency of the antenna
:8!3*C-=
] GPz>k
radiation efficiency=P(radiated)/P(delivered)
M[3w EX^
aKFA&Xnsl
in which the P(delivered)=1w
:g:h 0'G
nm|m1Z+U
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